4.9x^2+22.36x-10=0

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Solution for 4.9x^2+22.36x-10=0 equation: 



4.9x^2+22.36x-10=0

a = 4.9; b = 22.36; c = -10;
Δ = b2-4ac
Δ = 22.362-4·4.9·(-10)
Δ = 695.9696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22.36)-\sqrt{695.9696}}{2*4.9}=\frac{-22.36-\sqrt{695.9696}}{9.8}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22.36)+\sqrt{695.9696}}{2*4.9}=\frac{-22.36+\sqrt{695.9696}}{9.8}
$

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